2x^2+7x=26

Solution for 2x^2+7x=26 equation:

2x^2+7x=26

We move all terms to the left:

2x^2+7x-(26)=0

a = 2; b = 7; c = -26;
Δ = b2-4ac
Δ = 72-4·2·(-26)
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{257}}{2*2}=\frac{-7-\sqrt{257}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{257}}{2*2}=\frac{-7+\sqrt{257}}{4}
$